Question

(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0


please solve it step by step
so that I can also understand it,ans solve it on my own....​

Answer 1

Answer:

x = 6

Step-by-step explanation:

$(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0$

${x}^{2} + 5x + 6 + {x}^{2} -5x + 6 - 2 {x}^{2} - 2x = 0$

$12 - 2x = 0$

$2x = 12$

$x = 6$

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x²+x²-2x² +5x-5x -2x +6+6 = 0

=> 2x²-2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.