Question

(x + 2) (x + 3) + (x - 3)(x - 2)-2x(x + 1) = 0

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Answer 1

Let's solve your equation step-by-step.

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

Step 1: Simplify both sides of the equation.

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

(x)(x)+(x)(3)+(2)(x)+(2)(3)+(x)(x)+(x)(−2)+(−3)(x)+(−3)(−2)+−2x2+−2x=0 (Distribute)

x2+3x+2x+6+x2+−2x+−3x+6+−2x2+−2x=0

(x2+x2+−2x2)+(3x+2x+−2x+−3x+−2x)+(6+6)=0 (Combine Like Terms)

−2x+12=0

−2x+12=0

Step 2: Subtract 12 from both sides.

−2x+12−12=0−12

−2x=−12

Step 3: Divide both sides by -2.

−2x

−2

=

−12

−2

x=6

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Answer 2

Answer:

Given that,

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x 2 +2x+3x+6+x 2 −3x−2x+6−2x 2 −2x=0

⇒2x 2 −2x 2+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6

Step-by-step explanation:

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