Question

(x+2)(x+3)+(x-3)(x-2)-2x(x+1) equal to 0

Answer 1

(x+2)(x+3) + (x-3)(x-2) -2x(x+1) = 0 

$x^2 + 3x + 2x + 6 + x^2 -2x -3x + 6 -2x^2 -2x$=0

$x^2 + x^2 -2x^2 + 3x + 2x -3x -2x -2x + 6 + 6 = 0$

$-2x + 12 = 0$

-2x = -12

2x = 12 

x =12/2 

x = 6 


i hope this will help you


-by ABHAY

Answer 2

Hii friend,

(X+2)(X+3) + (X-3)(X-2) -2X(X+1) = 0

X(X+3) +2(X+3) +X(X-2) -3(X-2) -2X(X+1) = 0

X²+3X+2X+6+X²-2X-3X+6-2X²-2X = 0

2X²+5X+6-5X+6-2X²-2X= 0

-2X+12 = 0

X = 12/2

X = 6

HOPE IT WILL HELP YOU..... :-)