Question

(x+2)(x+3)+(x-3)(x-2)-2x(x+4)=0 solve this equation

Answer 1

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Answer 2

x
${x}^{2} + 5x + 6 + {x}^{2} - 5x - 6 - {2x}^{2} + 8x = 0 \\ 8x = 0 \\ x = \frac{0}{8}$