Question

(x+2) (x+3)-(x+3)(x-2)=​

Answer 1

Answer:

(x+2) (x+3)-(x+3)(x-2)=​ 4(x + 3)

Step-by-step explanation:

(x+2) (x+3) = x (x + 3) + 2 (x + 3)

= x (x) + x(3) + 2(x) + 2 (3)

$= x^2 + 3x + 2x + 6\\= x^2 + 5x + 6$

(x+3)(x-2)= x (x + 3) - 2 (x + 3)

= x (x) + x(3) -2(x) -2 (3)

$= x^2 + 3x - 2x -6\\= x^2 + x - 6$

So, (x+2) (x+3)-(x+3)(x-2)

$=(x^2 + 5x + 6) - (x^2 + x - 6)$

Change sign

$= x^2 + 5x + 6 - x^2 - x + 6$

Rearrange similar terms

$= x^2 - x^2+ 5x - x + 6 + 6$

= 4x  + 12

= 4(x + 3)

(x+2) (x+3)-(x+3)(x-2)=​ 4(x + 3)