Question

(x+2) (x+3) (x+4) (x+5) - 48 factorise​

Answer 1

Step-by-step explanation:

$(x + 2)(x + 5)(x + 3)(x + 4) - 48 \\ = > ({x }^{2} + 2x + 5x + 10)( {x}^{2} + 3x + 4x + 12) - 48 \\ = > ({x }^{2} + 7x + 10)( {x}^{2} + 7x + 12) - 48 \\ = > let \: ({x}^{2} + 7x) = a \\ = > (a + 10)(a + 12) - 48 \\ = > {a}^{2} + 10a + 12a + 120 - 48 \\ = > {a}^{2} + 22a + 72 \\ = > {a }^{2} + 18a + 4a +72 \\ = > a(a + 18) + 4(a + 18) \\ = > (a + 4)(a + 18) \\ putting \: value \: of \: a \\ = > ({x}^{2} + 7 x+ 4)( {x}^{2} + 7x + 18)$

plz make me brainliest