(x+2)(x-3)(x+5) is identical to x³+ax²-11x+b. Find the value of b.
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(x+2)(x-3)(x+5)
=(x^2+2x-3x-6)(x+5)
=(x^2-x-6)(x+5)
=x^3-x^2-6x+5x^2-5x-30
=x^3+4x^2-11x-30
as it is identical to
x^3+ax^2-11x+b
so, here a=4 and b= -30
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