Question

(x-2)(x+3)=(x-7)(x+7)​

Answer 1

Answer:

x2+3x-2x+6 = x2+7x-7x-49

x+6= -49

x = -54

Answer 2

$\sf\huge {\underline{\underline{{Solution}}}}$

=> (x-2)(x+3)= (x-7)(x+7

opening the brackets and expanding the terms

=> x(x+3)-2(x+3)= (x-7)(x+7)

=> x²+3x-2x-6= (x-7)(x+7)

=>x²+x-6= (x-7)(x+7)

Since,on the RHS it is in the form of a quadratic equation and on the LHS it is in the form of an identity :(a+b)(a-b)=a²-b²

=>x²+x-6 = x²-7²

=> x²+x-6= x²-49

Since ,x² lies on both sides so,it gets automatically cancelled:

=> x-6= -49

=> x= -49+6

=>x= -43

Check:

=>(x-2)(x+3)=(x-7)(x+7)

Taking RHS

=> (-43-2)(-43+3)

=>(-45)(-40)

= 1800

Taking LHS

=> (-43-7)(-43+7)

=> (-50)(-36)

=1800

Hence,At x= -43 LHS=RHS(Verified)