(x+2)(x-3)=x+kx-6then k is
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Answer:
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Answer:
The value of k is - 1.
Step-by-step-explanation:
The given equation is ( x + 2 ) ( x - 3 ) = x + kx - 6.
We have to find the value of k.
( x + 2 ) ( x - 3 ) = x + kx - 6
⇒ x ( x - 3 ) + 2 ( x - 3 ) = x + kx - 6
⇒ x² - 3x + 2x - 6 = x + kx - 6
⇒ x² - x - 6 = x + kx - 6
⇒ x² - x - 6 - x + 6 = kx
⇒ x² - 2x + 0 = kx
⇒ x² - 2x - kx = 0
⇒ x² - x - x - kx = 0
⇒ x ( x - 1 ) - x ( 1 + k ) = 0
⇒ ( x - 1 ) = 0 or ( 1 + k ) = 0
Now,
⇒( 1 + k ) = 0
⇒ 1 + k = 0
⇒ k = - 1
Now,
⇒ ( x - 1 ) = 0
⇒ x - 1 = 0
⇒ x = 1
∴ The value of k is - 1.
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Verification:
By substituting values of x & k in the LHS of the given equation, we get,
( x + 2 ) ( x - 3 )
⇒ ( 1 + 2 ) ( 1 - 3 )
⇒ 3 × ( - 2 )
⇒ - 6
∴ LHS = - 6
Now, by substituting values of x & k in the RHS of the given equation, we get,
x + kx - 6
⇒ 1 + ( - 1 ) × 1 - 6
⇒ 1 - 1 - 6
⇒ 0 - 6
⇒ - 6
∴ RHS = - 6
∴ LHS = RHS