Question

x^2 -x(4+ ✓2) +4✓2 = 0​

Answer 1

Answer:

x^2-4x-x√2+4√2=0

x(x-4)-√2(x-4)=0

(x-4)(x-√2)=0

x-4=0, x=4

x-√2=0, x=√2

Answer 2

Step-by-step explanation:

${x}^{2} - 4x - x \sqrt{2} + 4 \sqrt{2} = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x(x - 4) - \sqrt{2} (x - 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \:(x - \sqrt{2)} (x - 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: x - \sqrt{2} = 0 \: \: \: \: x = \sqrt{2} \: \: \: \: \: \: \: \: \: x - 4 = 0 \: \: \: \: x = 4$