Math, asked by umrakhan97, 5 months ago

(x - 2)(x-4) + 4x-8=0

Answers

Answered by Anonymous

2

Answer:

$\huge\mathbf{\boxed{\red{\boxed{\green{Answer}}}}}$

Step-by-step explanation:

$(x - 2)(x - 4) + 4x - 8 = 0 \\ {x}^{2} - 6x + 8 + 4x - 8 = 0 \\ {x}^{2} - 2x = 0 \\ x(x - 2) = 0 \\ hence \: x = 2 \: and \: 0$

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