(x-2) (x-4) (x-3) represents the length breadth and height of a cuboid respectively. of its volume represents a polynomial then find the sum of zeroes and product of zeroes. plz answer quickly
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length = x-2
breadth = x-4
height = x-3
Volume = lbh = (x-2)(x-4)(x-3)
So the polynomial f(x) = (x-2)(x-4)(x-3)
zeroes of f(x) are 2, 4 and 3.
sum of zeroes = 2+4+3 = 9
product of zeroes = 2×4×3 = 24
breadth = x-4
height = x-3
Volume = lbh = (x-2)(x-4)(x-3)
So the polynomial f(x) = (x-2)(x-4)(x-3)
zeroes of f(x) are 2, 4 and 3.
sum of zeroes = 2+4+3 = 9
product of zeroes = 2×4×3 = 24
Answered by
1
length= x-2
breadth= x-4
height= x-3
the volume represents a polynomial
thus volume =(x-2)(x-3)(x-4)
=x³-9x²+26x-24
the zeroes f the polynomial are =2 ,3 ,4
then the sum of zeroes = 9
product of zeroes =24
breadth= x-4
height= x-3
the volume represents a polynomial
thus volume =(x-2)(x-3)(x-4)
=x³-9x²+26x-24
the zeroes f the polynomial are =2 ,3 ,4
then the sum of zeroes = 9
product of zeroes =24
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