Question

(x-2)(x-4)(x-6)+2 find real root​

Answer 1

Answer:

Correct option is

B

2

Let, 7−x=a

The equation becomes

(a−1)

4

+(a+1)

4

=16

⇒a

4

+6a

2

+1=8

⇒a

4

+6a

2

−7=0

⇒(a

2

+7)(a

2

−1)=0

Now, a

2

>0,

So, a

2

=1

Hence, a=1,a=−1

⇒x=6 or x=8.

Hence, there are two real solutions of x.

Step-by-step explanation:

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