Question

x-2/x-4+x-6/x-8=20/3

Answer 1

$\frac{x-2}{x-4}+\frac{x-6}{x-8}=\frac{20}{3}\\\\\frac{x^2-10x+16+x^2-10x+24}{x^2-12x+32}=\frac{20}{3}\\\\simplify\\\\7x^2-90x+260=0\\\\x=\frac{45+-\sqrt{205}}{7}$

the answer is not a simple value.. irrational number.

Answer 2

pls mark it as best 
it will be irrational
you can see solution on the page attached below