x+2(x-5)when x=5
pls tell this and 2nd question. Is in the pic
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x^2 + x = 5
=> (x+3)(x-2)=-1
=> 1/(x+3) = 2-x
Now,
(x+3)^3 + (1/(x+3))^3
=> (x+3)^3 + (2-x)^3
Using a^3 + b^3 = (a+b)(a^2-ab+b^2),
=> (x+3+2-x)((x+3)^2 - (x+3)(2-x) + (2-x)^2)
=> 5*(2*x^2+2*x+12)
Taking 2 common from inside, and replacing x^2 + x = 5,
=> 10*(5+6)
=> 110
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