Question

x^2-x-6=0 find the value of the sum​

Answer 1

Answer:

${x}^{2} - x - 6 = 0$

${x}^{2} - (3 - 2)x - 6 = 0$

${x}^{2} - 3x + 2x - 6 = 0$

$x(x - 3) + 2(x - 3) = 0$

$(x - 3)(x + 2) = 0$

$(x - 3) = 0 \: and \: (x + 2) = 0$

$x = 3 \: and \: x = - 2$

Ans. 3 and -2

Hope it helps.

Answer 2

Answer:

3-2 = 1

Step-by-step explanation:

x^2 -x -6 = 0

x^2 -3x + 2x - 6 = 0

x ( x- 3) + 2 (x - 3) = 0

(x+2) (x-3) = 0

x = 3 , -2