Question

x^2 +x-6 find the zeros of tge polynomial

Answer 1

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Answer 2

x² + x - 6 = x² + 3x - 2x - 6
= x(x + 3) - 2(x + 3)
= (x-2) (x+3)

For zeros
x - 2 = 0
x = 2

x + 3 = 0
x = -3

✴ The zeros of the given polynomial are 2 and -3.

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