x^2+x-6 ..mid term splitting method plz help
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Answer:
Step-by-step explanation:
✏ In a quadratic equation
ax2+bx+c=0
to solve one splits the middle term in two parts so that their sum is b and product is a c .
Hence, in x²+x−6=0
one needs to split
1×(−6)= −6
in two parts whose sum is 1
It is apparent that these are 3 and −2
Hence x2+x−6=0 can be written as
x2+3x−2x−6=0
or
x(x+3)−2(x+3)=0
or
(x−2)(x+3)=0
i.e. either
x−2=0
i.e.
x=2
or
x+3=0
i.e.
x= −3
Hope it's helpful↑(◍•ᴗ•◍)❤࿐
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