Question

x^2-x-6 x^2+6x+5 ______ × _______ x^2+4x-5 x^2-4x+3​

Answer 1

Step-by-step explanation:

Fun with logarithms!

log((x2−4x+5)(x2+x−30))=log1

(x2+x−30)log(x2−4x+5)=0

x2+x−30=0 or x2−4x+5=1

(x+6)(x−5)=0 or (x−2)2=0

This gives us a potential solution set of {−6,2,5} .

One thing we need to check: since 00 is undefined, we need to make sure that x2−4x+5≠0 when x2+x−30=0 . This is an easy check.