(x-2)(x-9) minimum value
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Answered by
18
(x -2) (x -9)
= (x^2 2x - 9x + 18)
=(x^2 - 11x + 18)
= x^2 - 11x + 121/4 - 121/4 + 18
(x - 11/2)^2 - 49/4
x = 11/2 = -49/4
= (x^2 2x - 9x + 18)
=(x^2 - 11x + 18)
= x^2 - 11x + 121/4 - 121/4 + 18
(x - 11/2)^2 - 49/4
x = 11/2 = -49/4
Moumita07:
hlo
Answered by
1
Answer:
Above function is minimum at
Step-by-step explanation:
Given (x-2)(x-9)
we have to find the minimum value
To get the minimum value we have to differentiate the above polynomial and put it equals to 0 and then find the x value.
Now, equate f'(x) to 0
⇒ ⇒
To check the above value whether it is maximum or minimum at the above value we have to double differentiate f(x).
f''(x)=2 which is positive.
Hence, above function is minimum at
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