Question

x^2 + x − (a + 2) (a + 1) = 0

Answer 1

Answer:

Top answer · 668 votes

Given x^2 + x - (a + 2)(a + 1) = 0 , Here, a = 1, b = 1, c = - (a + 2)(a + 1) x = -b±√(b^2 - 4ac)2a = -1±√(1^2 - 4{(a + 2)(a + 1)})2(1) = -1±√(1 answer hope i helped you

Answer 2

Given x^2

+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x=

2a

−b±

b

2

−4ac

=

2(1)

−1±

1

2

−4{(a+2)(a+1)}

=

2

−1±

1−4{−(a

2

+3a+2)

x=

2

−1±

1+4a

2

+12a+8

=

2

−1±

4a

2

+12a+9

=

2

−1±

(2a+3)

2

=

2

−1±(2a+3)

∴x=

2

−1+2a+3

and x=

2

−1−2a−3

∴x=

2

2a+2

and x=

2

−2a−4

x=a+1x=−(a+2)

∴ The roots of x

2

+x−(a+2)(a+1)=0 are (a+1) and −(a+2)