Question

x^2+x-(a+2) (a+1)=0​

Answer 1

$<b >HEYA !!!$

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x²+x-(a+1)(a+2)=0

x²-(a+1)x+(a+2)x-(a+1)(a+2)=0

→x[x-(a+1)]+(a+2)[x-(a+1)]=0

→[x-(a+1)][x+(a+2)]=0

[x-(a+1)] =0 or [x+(a+2)]=0

therefore,

x= a+1 or x = -(a+2)

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