x +2/√x square+ 2x + 3. dx
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I'm asked to evaluate this integral: ∫x2−2x−3−−−−−−−−−√dx
I don't see any other way to solve this except by trigonometric substitution, which is precisely what I did once I completed the square and got 4−(x−1)2−−−−−−−−−−√ as the integrand.
I then performed a substitution with (x−1)=2sin(θ).
But all of the answer choices contain some natural logarithms in them. I have no clue how that's possible.
What other methods are there for solving this problem?
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