Math, asked by rita7675, 1 month ago

x^-2/x^y=1/x^12 , find the value of y​

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Answered by akumaokoku
1

Answer:

10

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Answered by Anonymous
0

\frac{{x}^{-2}}{{x}^{y}}=\frac{1}{{x}^{12}}

{x}^{-2-y}=\frac{1}{{x}^{12}}

-2-y=\log_{x}{\frac{1}{{x}^{12}}}

-y=\log_{x}{\frac{1}{{x}^{12}}}+2

y=-\log_{x}{\frac{1}{{x}^{12}}}-2

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