Math, asked by dk418542, 2 months ago

x^2-xb -ax+ab+x^2-cx-bx+bc+x^2-ax-cx-ca=0​

Answers

Answered by rofessordebbarma
0

Answer:

0

Step-by-step explanation:

x^2 - xb - ax + ab + x^2 - cx - bx + bc + x^2 - ax - cx - ca

= (x^2-xb-ax)+(ab+x^2-cx)-(bx+bc+x^2)-(ax-cx-ca)

= x^2-xb-ax+ab+x^2-cx-bx-bc-x^2-ax+cx+ca

= 0.

R.H.s

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