Question

x^2+xy^2-y^3=73, if x=4 then find the value of y???​

Answer 1

Step-by-step explanation:

${x}^{2} + {xy}^{2} - {y}^{3 } = 73 \\ substitutin g \: the \: value \: of \: x \: = 4 \\ = > {4}^{2} + {4y}^{2} - {y}^{3} = 73 \\ = > 16 + {4y}^{2} - {y}^{3} = 73 \\ = > {4y}^{2} - {y}^{3} = 73 - 16 \\ = > {4y}^{2} - {y}^{3} = 57 \\ = > {y}^{2} (4 - y) = 57$