Question

x^2 -xy +3y^2 - 5y =0 at x=2

Answer 1

Answer:

y=4/3,y=1

Step-by-step explanation:

2^2-2×y+3y^2-5y=0 as value of x=2

=4-2y+3y^2-5y=0

=3y^2-7y+4=0

=3y^2-4y-3y+4=0

=3y(y-1)-4(y-1)=0

=(3y-4)(y-1)=0

=y=4/3,y=1