Question

x^2+xy+xz+yz factorise ​

Answer 1

$\huge\boxed{\mathfrak{\fcolorbox{red}{skyblue}{Here\:is\:Ans}}}$


$\mathcal{\pink{\bold{Factorise}}}$


$= x {}^{2} + xy + xz + yz$

$= x\times (x + y) + z \times (x + y)$

$= (x + y)(x + z)$


$\mathcal{\blue{\bold{\star\:Madhura20}}}$

Answer 2

The answer to the factorisation is, (x+y) (x+z)

Given : The algebraic expression is, (x²+xy+xz+yz)

To find : The factorisation of the given algebraic expression.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is factorise the given algebraic expression)

Here, we will be using the general algebraic method. (we will be using algebraic identities is necessary)

Now,

= x² + xy + xz + yz

= x (x+y) + z (x+y)

= (x+y) (x+z)

(This cannot be further simplified. That's why this will be considered as the final result.)

Hence, the answer to the factorisation is, (x+y) (x+z)