x^2+y^2+10=2√2x+4√2y, find x+y
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0
Answer:
x
2
+y
2
+10=2
2
x+4
2
y
=>x
2
−2
2
x+y
2
−4
2
y+10=0
=>x
2
−2⋅x⋅
2
+(
2
)
2
+y
2
−2⋅y⋅2
2
+(2
2
)
2
=0
=>(x−
2
)
2
+(y−2
2
)
2
=0
=>x−
2
=0 and y−2
2
=0
=>x=
2
and y=2
2
∴x+y=3
2
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