Question

X^2+Y^2=10
2x+3y=1
Solve the simultaneous equation for x and y

Answer 1

Answer: The answers are a bit weird...

x = (-1 + √10)  and y = (1 - 2√10)

Step-by-step explanation:   x² + y² = 10

                                           ⇒ x + y = √10    [Squaring both sides]   ...(i)

                           2x + 3y = 1   ...(ii)

From equ. (i) we get x = (√10 - y)   ...(iii)

putting the value of x in equ. (ii) we get

2 × (√10 - y) + 3y = 1

⇒ 2√10 -2y +3y = 1

⇒ 2√10 + y = 1

⇒ y = (1 - 2√10)

Then, putting the value of y in equ. (iii), we get

x = (√10 - y)

⇒ x = √10 - (1 - 2√10)

⇒ x = (- 1 + √10)  

HOPE U UNDERSTAND :-)