x^2-y^2/100
please send the answer I am giving you 20 to you and brainliest also answer can come this {x+y/10} {x-y/10}
use this formula ( a+b)^2
Answers
X²-Y²=(X+Y)(X-Y) Here is the prove for that. (x+y)(x-y)=x²+2xy-2xy-y²
Answer:
Always the most comprehensive way about these is not to seek x nor y but instead a, b, x and y.
The Reasoning…
The reasoning is that the following is so:
Table I: Equational Substitues for x, y and related terms
[math]x=a-b=y-2b[/math]
[math]y=a+b=x+2b[/math]
[math]x+y=2a[/math]
[math]xy=a^2-b^2[/math]
Due that, the formula for xy is capable using Substitutes
Figure 1: xy with Substitutes
[math]xy=\frac {(x+y)^2}{4} - b^2[/math]
And the formula for x+y is capable substitutes as
Figure 2: x+y with Substitutes (derived from Figure 1)
[math]x+y=\sqrt {4xy+4b^2}[/math]
and because you were supplied the value for a, via (x+y)/2 and also were supplied both of xy and x+y you can easily resolve either of those two equations for [math]b^2[/math] as the subtrahend in xy.
And by using Table I, You also derive x and y from the a and b you resolved as follows:
[math]x+y=\sqrt {4xy+4b^2}=10=\sqrt {(4•16)+4b^2}[/math]
We knowing that 10[math]=\sqrt {100}[/math]
Also know that [math]4b^2=100-64=36[/math]
Making [math]b^2=9=3^2[/math] alongside a=5=10/2.
We thus have
a=5
b=3
x=2
y=8
And we know full well it is resolved because x+y=10 and xy=16.
If we wanted to draw the 3 Squares respectively [math]x^2, a^2[/math], and [math]y^2[/math] to reveal the actual area of [math]y^2-a^2[/math] and [math]y^2-x^2,[/math] we would have all the information to draw these by a ruler and three Colored pencils for use on a paper provided.
I hope this helps. Please mark the answer as the branliest