Question

x^2 - y^2/100 using identitiy

Answer 1

Hyy Dude

Hii....☺

Hii....☺Here is your solution.......☺

Hii....☺Here is your solution.......☺===============================

Hii....☺Here is your solution.......☺===============================✴ To factorise :

Hii....☺Here is your solution.......☺===============================✴ To factorise :x² - y²/100

Hii....☺Here is your solution.......☺===============================✴ To factorise :x² - y²/100=> x² - ( y/10)²

Hii....☺Here is your solution.......☺===============================✴ To factorise :x² - y²/100=> x² - ( y/10)²=> ( x + y/10 ) ( x - y/ 10)

Hii....☺Here is your solution.......☺===============================✴ To factorise :x² - y²/100=> x² - ( y/10)²=> ( x + y/10 ) ( x - y/ 10)♦ Note: a² - b² = (a + b) (a - b) here this identity is used.

Hii....☺Here is your solution.......☺===============================✴ To factorise :x² - y²/100=> x² - ( y/10)²=> ( x + y/10 ) ( x - y/ 10)♦ Note: a² - b² = (a + b) (a - b) here this identity is used.===============================

Hii....☺Here is your solution.......☺===============================✴ To factorise :x² - y²/100=> x² - ( y/10)²=> ( x + y/10 ) ( x - y/ 10)♦ Note: a² - b² = (a + b) (a - b) here this identity is used.===============================Thanks...☺

Plz marked in brainlest answer

Answer 2

Answer:

hii here is your ans

Step-by-step explanation:

to factorise x^2-y^2/100

=> x^2-y^2/10

=>x+y/10,x-y/10

Note :a^2-b^2=[a+b] [a-b] hear this identity is used