Math, asked by gitanjalisethi09, 1 month ago

( x^2+ y^2-2^2)-(32^2-2x^2-4y^2)+(4y^2+x^2+2^2).​

Answers

Answered by beauty1238
0

 \mathcal{Let's  \: simplify \:  step-by-step.}

( x^2+ y^2-2^2)-(32^2-2x^2-4y^2)+(4y^2+x^2+2^2).

=x^2+y^2+−4+−1024+2x^2+4y^2+4y^2+x^2+4

 \mathcal{Combine \:  Like \:  Terms:}

=( \blue{x^2+2x^2+x^2})+(\green{y^2+4y^2+4y^2})+(\red{−4+−1024+4})

= \blue{4x^2}+\green{9y^2}+\red{−1024}

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