Question

X^2 - Y^2 = 28 and X - Y = 4, find the value of ( 2x + 2y)^2

Answer 1

x-y = 4

x²-y² = 28

=> (x+y)(x-y) = 28

=> 4(x+y) = 28

=> (x+y) = 7

(x+y)+(x-y) = 7+4 = 11 => 2x = 11=> x = 11/2

y = 7-x = 7-(11/2) = (14-11)/2 = 3/2

(2x+2y)² = (2×11/2 + 2×3/2)² = (11+3)² = 14² = 196

Answer 2

Step-by-step explanation:

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