Question

x^2+y^2+2x+1=0 then the value of x^31+x^35​

Answer 1

The value of  $x^{31}$ + $x^{35}$  is "- 2".

Step-by-step explanation:

We have,

$x^{2}$ + $y^{2}$ + 2x + 1 = 0

⇒( $x^{2}$ + 2x + 1 )+ $y^{2}$ = 0

⇒ $(x + 1)^{2}$ + $y^{2}$  = 0

⇒$(x + 1)^{2}$ = 0 or  $y^{2}$  = 0

⇒ (x + 1) = 0

∴ x = - 1

∴ $x^{31}$ + $x^{35}$

= $(- 1)^{31}$ + $(- 1)^{35}$

= - 1  - 1

= - 2

Hence, the value of  $x^{31}$ + $x^{35}$  is -2.