(x^2+y^2+2xy) -4xy is
Answers
Answer:
Step-by-step explanation:
STEPS USING THE QUADRATIC FORMULA
=x
2
+y
2
−2xy−1=0
All equations of the form ax
2
+bx+c=0 can be solved using the quadratic formula:
2a
−b±
b
2
−4ac
. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x
2
+(−2y)x+y
2
−1=0
This equation is in standard form: ax
2
+bx+c=0. Substitute 1 for a, −2y for b, and −1+y
2
for c in the quadratic formula,
2a
−b±
b
2
−4ac
.
x=
2
−(−2y)±
(−2y)
2
−4(y
2
−1)
Square −2y.
x=
2
−(−2y)±
4y
2
−4(y
2
−1)
Multiply −4 times −1+y
2
.
x=
2
−(−2y)±
4y
2
+4−4y
2
Add 4y
2
to 4−4y
2
.
x=
2
−(−2y)±
4
Take the square root of 4.
x=
2
−(−2y)±2
Now solve the equation x=
2
2y±2
when ± is plus. Add 2y to 2.
x=
2
2y+2
Divide 2+2y by 2.
x=y+1
Now solve the equation x=
2
2y±2
when ± is minus. Subtract 2 from 2y.
x=
2
2y−2
Divide −2+2y by 2.
x=y−1
The equation is now solved.
x=y+1
x=y−1
SOLVE FOR Y
y=x−1
y=x+1STEPS USING THE QUADRATIC FORMULA
=x
2
+y
2
−2xy−1=0
All equations of the form ax
2
+bx+c=0 can be solved using the quadratic formula:
2a
−b±
b
2
−4ac
. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x
2
+(−2y)x+y
2
−1=0
This equation is in standard form: ax
2
+bx+c=0. Substitute 1 for a, −2y for b, and −1+y
2
for c in the quadratic formula,
2a
−b±
b
2
−4ac
.
x=
2
−(−2y)±
(−2y)
2
−4(y
2
−1)
Square −2y.
x=
2
−(−2y)±
4y
2
−4(y
2
−1)
Multiply −4 times −1+y
2
.
x=
2
−(−2y)±
4y
2
+4−4y
2
Add 4y
2
to 4−4y
2
.
x=
2
−(−2y)±
4
Take the square root of 4.
x=
2
−(−2y)±2
Now solve the equation x=
2
2y±2
when ± is plus. Add 2y to 2.
x=
2
2y+2
Divide 2+2y by 2.
x=y+1
Now solve the equation x=
2
2y±2
when ± is minus. Subtract 2 from 2y.
x=
2
2y−2
Divide −2+2y by 2.
x=y−1
The equation is now solved.
x=y+1
x=y−1
SOLVE FOR Y
y=x−1
y=x+1