x^2+y^2-2xy-4z^2 factorise
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Answer:
(x+y)^2+2(xy-2z^2) this is the answer
Answered by
1
The first three terms of the expression is in the form (x+y)
2
and the fourth term is a perfect square.
Hence, x
2
+2xy+y
2
−4z
2
=(x+y)
2
−(2z)
2
=[(x+y)+2z][(x+y)−2z]
=(x+y+2z)(x+y−2z)
Step-by-step explanation:
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