Question

(x^2-y^2)^3 + (y^2-z^2)^3 + ( z^2-x^2)^3

Answer 1

Step-by-step explanation:

(x²-y²)³+(y²-z²)³+(z²-x²)³

It is of the form a³+b³+c³ where a+b+c=0

So , it will be we equal to :

3(x²-y²)(y²-z²)(z²-x²)