Question

X^2+Y^2= 4, when the axes are translated to the point (3,-4), then find the original
equation of the curve,​

Answer 1

Answer:

X^2 + Y^2 + 6X - 8Y - 21 = 0

Step-by-step explanation:

When the point changes to (x,y) changes to (X,Y) on shifting the origin to (h,k)

Then,

x = X + h, y = Y + k

so,

x = X + 3, y = Y - 4

So, the equation transform to

=> (X + 3)^2 + (Y - 4)^2 = 4

=> X^2 + 9 + 6X + Y^2 + 16 - 8Y = 4

=> X^2 + Y^2 + 6X - 8Y - 21 = 0

Hope it helps!