Question

x^2+y^2=57 and xy=16 find x-y

Answer 1

HEY Buddy...!! here is ur answer

Answer : 5

Given that : x²+y² = 57 and xy = 16

As we know that :

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ \\ = > {(x - y)}^{2} = 57 - 2 \times 16 \\ \\ = > {(x - y)}^{2} = 57 - 32 \\ \\ = > {(x - y)}^{2} = 25 \\ \\ = > (x - y) = 5$

I hope it will be helpful for you...!!

THANK YOU ✌️✌️

Answer 2

Given
${x}^{2} + {y}^{2} = 57 \\ xy = 16$
Or,
$2xy = 32$
Now as,
$(x - y)^{2} = {x }^{2} - 2xy + {y}^{2}$
$(x - y)^{2} = 57 - 32 \\ {(x - y)}^{2} = 25$
$x-y=\pm 5$