Question

x^2-y^2+6y-9 factoise without using factor theoram​

Answer 1

${x}^{2} - {y}^{2} + 6y - 9$

${x}^{2} - ( {y}^{2} - 6y + 9)$

${x}^{2} - ( {y - 3}^{2} )$

$(x - (y - 3) \times (x + (y - 3))$

$(x - y + 3)(x + y - 3)$

Answer 2

Answer:

$\small\underline\mathcal\pink{Answer}$

x² - y² + 6y - 9

x² - ( y² - 6y + 9 )

x² - ( y - 3² )

( x - ( y - 3 ) × ( x + ( y - 3 ) )

( x - y + 3 ) ( x + y - 3 )

$\small\underline\mathcal\orange{ hope \: it \: helps \: you}$