x^2-y^2+6y-9.Factorize
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Answered by
300
x² - y² + 6y - 9
= x² - ( y² - 6y + 9)
=x² - ( y² -2.3.y + 3²)
= x² - ( y - 3)²
=( x - y +3)( x + y - 3)
hence, ( x - y+3) and ( x +y -3) are two factors of x²-y²+6y -9/
= x² - ( y² - 6y + 9)
=x² - ( y² -2.3.y + 3²)
= x² - ( y - 3)²
=( x - y +3)( x + y - 3)
hence, ( x - y+3) and ( x +y -3) are two factors of x²-y²+6y -9/
Answered by
172
hi friend,
x²-y²+6y-9
=x²-(y²-6y+9)
=x²-(y²-6y+(3)²)
=x²-(y²-2(y)(3)+(3)²)
=x²-(y-3)²
=(x+y-3)(x-y+3)
hope it helps you
x²-y²+6y-9
=x²-(y²-6y+9)
=x²-(y²-6y+(3)²)
=x²-(y²-2(y)(3)+(3)²)
=x²-(y-3)²
=(x+y-3)(x-y+3)
hope it helps you
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