Question

x^2+y^2=8
x-y=4
So, find the value of this

(x+y)^2

Answer 1

Hope this answer helps you.

Answer 2

Answer:

x - y =4

x =4-y

(4-y)^2 + y^2 = 8

16-8y+ y^2 +y^2 = 8

2(y^2) - 8y + 8=0

y^2 - 4y + 4 = 0

y^2-2y-2y+4=0

y(y-2)-2(y-2)=0

y-2=0

y=2

x=6

value=64