(x ^ 2 - y ^ 2) Find the HCF of 2x ^ 3 + x ^ 2 - 3x and x ^ 3 - x
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Answer:
Let f(x)= 2x
2
−3x−2
g(x)= (x−2)(x+1)
Factor of 2x
2
−3x−2=(2x+1)(x−2)
So, H.C.F = (x−2)
L.C.M = (x−2)(2x+1)(x+1)
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