Math, asked by narendrasinghpal685, 2 months ago

X 2 – Y 2 is equal to-: *
(I). ( X – Y ) ( X + Y )
(ii). ( X + Y ) ( X + Y )
(iii). ( X – Y ) ( X – Y )
(iv). NONE​

Answers

Answered by monuyadav87696
0

Step-by-step explanation:

Wyzant

SQUARE ROOTS

Xin W. asked • 03/17/14

does square root of (x^2+y^2) equal to x+y?

I don't think so, because if you let x=1, y=1, square root of (x^2+y^2)=square root of 2, which doesn't equal to x+y

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3 Answers By Expert Tutors

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Parviz F. answered • 03/18/14

TUTOR 4.8 (4)

Mathematics professor at Community Colleges

SEE TUTORS LIKE THIS

( X + Y ) ^2 = ( X + Y ) ( X + Y ) = X ( X +Y ) + Y ( X + Y ) = X^2 + 2X Y + Y ^2

X + Y = √( X + Y ) ^2 = √( X^2 + 2XY + Y ^2 ) ≠ √( X^2 + Y^2)

By Pythagoras Theorem:

X^2 + Y ^2 = Z ^2 / Z is the hypotenuse of a right triangle with X , Y as legs

Z = √(X ^ 2 + Y ^2)

If letting √( X^2 + Y ^2 ) equals X +y is in violation of Pythagoras theorem with implication that

length of the hypotenuse equals the Sum of the length of the legs, rather than square of the

hypotenuse being equal the Sum of the square of 2 length.

One Simple counter example defies that .

let X = 3 Y = 4

√(X^2 + Y ^2) = √ (3^2 + 4 ^2) = √25 =5

( √X ^2 )+( √Y ^2 ) = X + Y = 4 +3 =7

Students should remember that They can multiply and divide Radicals. but can not add or subtract.

Answered by yashvishah1000
0

Answer:

 {x}^{2}   -  {y}^{2}  = (x + y)(x - y)

Hope it helps you.

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