Question

x^2+y^2/x^2-y^2= 17/8 find the value of x (1) x/y​

Answer 1

Answer:

Step-by-step explanation:

(i) x2 + y2/x2 – y2 = 17/8

Applying componendo and dividendo rule,

x2 + y2 + x2 – y2/x2 + y2 – x2 + y2 = 17 + 8/17 – 8

2x2/2y2 = 25/9

x2/y2 = 25/9

x/y = 5/3

x : y = 5 : 3

(ii) Taking cube on both sides,

x3/y3 = 125/27

Applying componendo and dividendo rule,

x3 + y3/x3 – y3 = 125 + 27/125 – 27

x3 + y3/x3 – y3 = 152/98

Answer 2

Answer:

Step-by-step explanation:

x^2+y^2)/(x^2-y^2)=17/8

17*(x^2+y^2)=8*(x^2-y^2)

17x^2+17y^2=8x^2-8y^2

17x^2-8x^2=-8y^2-17y^2

9x^2=-25y^2

(3x)^2=(5y)^2

3x=5y

x:y=5/3