Question

(x^2-y^2)/(x^2+y^2)+(x^2+y^2)/x^2-y^2=2^1/2then find x^8-y^8/x^8+y^8

Answer 1

Answer:

Step-by-step explanation:

Taking lcm

X^4+y^4/x^4-y^4=1/√2

Using componendo and dividendo

x^4/y^4=1+√2/√2-1

Squaring both side

And again using componendo and dividendo

Hope it will help you