Question

X^2-y^2,(x-y)^2 find lcm

Answer 1

Answer:

$1st expression: x^{2} -y^{2} \\ =(x+y)(x-y)\\2nd expression: ( x-y)^{2} \\ =(x-y)(x-y)\\L.C.M=(x-y)(x-y)(x+y)\\ =(x^{2} -y^{2} )(x-y)$

Step-by-step explanation:by factorizing first expression or using formula, we get , (x+y)(x-y)

similarly, (x-y) (x-y) in second expression

while taking lcm, taking  (x-y)common at first and the remaining  (x-y) and  (x+y) and multiplying them we get, (x^2-y^2) (x-y)