Question

x^2+y^2+z^2=10, x+y+z=12.Find xy+yz+zx.​

Answer 1

Answer:

${x}^{2} + {y}^{2} + {z}^{2} = 10 \\ x + y + z = 12 \\ xy + yz + zx =find \\ we \: know \: that \\ {(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2(xy + yz + zx) \\ {12}^{2} = 10 + 2(xy + yz + zx) \\ 144 - 10 = 2(xy + yz + zx) \\ \frac{134}{2} = xy + yz + zx \\ 67 = xy + yz + zx$