Math, asked by vikash36, 1 year ago

(x^2+y^2-z^2)^2-(x^2-y^2+z^2)

Answers

Answered by QHM
1
ANSWER:
After simplying the question we get :
==>x^2+y^2-z^2-x^2-y^2+z^2.
==>0.

vikash36: send all simplify
vikash36: bro
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